What is the potential energy for an 800 kg elevator at the top of Chicago's Sears tower , 440 m above street level? Let the energy be zero at street level.
m g h = 88 * 9.8 * 440
my guess is that putting the energy@ 0 is just to throw you
To calculate the potential energy of the elevator at the top of Chicago's Sears Tower, we need to use the formula:
Potential Energy = mass * gravity * height
Where:
mass = 800 kg (mass of the elevator)
gravity = 9.8 m/s² (acceleration due to gravity)
height = 440 m (height above street level)
Substituting the given values into the formula, we can calculate the potential energy:
Potential Energy = 800 kg * 9.8 m/s² * 440 m
First, multiply 800 kg by 9.8 m/s²:
Potential Energy = 7,840 kg*m²/s² * 440 m
Next, multiply 7,840 kg*m²/s² by 440 m:
Potential Energy = 3,449,600 kg*m²/s²
Therefore, the potential energy of the 800 kg elevator at the top of Chicago's Sears Tower, 440 m above street level, is 3,449,600 kg*m²/s².
To calculate the potential energy of an object, we can use the formula:
Potential Energy = mass × gravity × height
In this case, the mass of the elevator is 800 kg and the height is 440 m.
The next value we need is the acceleration due to gravity, typically denoted as "g". On Earth, the value of gravity is approximately 9.8 m/s².
Now we can substitute the values into the formula:
Potential Energy = 800 kg × 9.8 m/s² × 440 m
Simplifying the calculation:
Potential Energy = 3,519,200 joules
Therefore, the potential energy for an 800 kg elevator at the top of Chicago's Sears Tower, 440 m above street level, is 3,519,200 joules.