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A crate with mass 32.5 kg initially at rest on a warehouse floor is acted on by a net horizontal force of 140 . How far does the crate travel in 10.0s? What is its speed at the end of 10.0s?

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colleen

  1. F=ma,or acceleration=force/mass

    distance=1/2 a*t^2

    vf=a*t

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    bobpursley

  2. F=ma
    a=F/m
    a= 140Kg.m/s² / 32.5kg
    a= 4.30769m/s²

    d=Vot + 1/2at²
    d=1/2at²
    d=1/2(4.31m/s²)(10s)
    d= 215.5m

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    Mercy

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