How do you factor (64-tsquare)?
is it (t+8)(t-8) or (8-t) (8+t) or is the same thing?
Why don't you just expand each of your choices and see which one gives you the correct result?
To factor the expression (64 - t^2), we need to find two expressions whose multiplication results in 64 - t^2. Let's expand each of the given choices and see which one gives us the correct result.
Choice 1: (t + 8)(t - 8)
Expanding this expression using the FOIL method (First, Outer, Inner, Last), we get:
(t + 8)(t - 8) = t^2 - 8t + 8t - 64
Combining like terms, we have:
t^2 - 64
This does not match the original expression (64 - t^2).
Choice 2: (8 - t)(8 + t)
Expanding this expression using the FOIL method, we get:
(8 - t)(8 + t) = 64 + 8t - 8t - t^2
Combining like terms, we have:
64 - t^2
This matches the original expression (64 - t^2).
Therefore, the correct factorization of (64 - t^2) is (8 - t)(8 + t).