How many kilojoules of energy are released from the carbon carbon single bonds when Glucose (C6H12O6) is burned?
how would i do this?
Look up the bond energy for C-C bond and multiply by 5.
okay, but why would i multiply by 5?
Aren't there C-C bonds? Glucose isn't a linear molecule but if it were, it would be C-C-C-C-C-C so five bonds hold it together. Here is the glucose molecule.
http://en.wikipedia.org/wiki/Glucose
To determine the amount of energy released from the carbon-carbon single bonds when glucose (C6H12O6) is burned, we need to first calculate the amount of energy released per mole of glucose.
1. Determine the balanced chemical equation for the combustion of glucose:
C6H12O6 + 6O2 -> 6CO2 + 6H2O
This equation shows that 1 mole of glucose reacts with 6 moles of oxygen gas to produce 6 moles of carbon dioxide and 6 moles of water.
2. Find the enthalpy change (∆H) for the combustion of glucose:
The enthalpy change, commonly known as heat of combustion, represents the amount of energy released when a substance is completely burned in excess oxygen.
The standard enthalpy change (∆H°) for the combustion of glucose is approximately -2800 kilojoules per mole. This value indicates that for every mole of glucose burned, 2800 kilojoules of energy are released.
3. Calculate the energy released from the carbon-carbon single bonds:
Glucose consists of 6 carbon atoms connected by single bonds. In the combustion process, these carbon-carbon single bonds are broken, resulting in energy release.
Since each mole of glucose contains 6 carbon atoms, we need to distribute the total energy release evenly across these carbon-carbon bonds. So, the energy released from each carbon-carbon single bond when glucose is burned is approximately (-2800 kJ) / 6 -> -466.67 kJ (rounded to two decimal places).
Therefore, approximately 466.67 kilojoules of energy are released from each carbon-carbon single bond when glucose is burned.
Note: The negative sign indicates that energy is released (exothermic process) during the combustion.