A landscaper is digging holes it takes him one hour to dig a hole 2 feet deep, 2 feet long and 2 feet wide. Assuming everything remains the same, how many hours would it take him to dig a hole 4 feet deep, 4 feet long and 4 feet wide?

This question has been answered this morning. See:

http://www.jiskha.com/display.cgi?id=1250848143

To find out how many hours it would take for the landscaper to dig a larger hole with dimensions 4 feet deep, 4 feet long, and 4 feet wide, we can use the concept of ratios.

Let's start by finding the ratio of the volume of the original hole (2 ft x 2 ft x 2 ft) to the volume of the larger hole (4 ft x 4 ft x 4 ft):

Volume of original hole: 2 ft x 2 ft x 2 ft = 8 cubic feet
Volume of larger hole: 4 ft x 4 ft x 4 ft = 64 cubic feet

The ratio of the volumes is 8 cubic feet / 64 cubic feet = 1/8.

This means that the larger hole is 8 times the size of the original hole. Therefore, it would take 8 times longer to dig the larger hole.

Since the original hole took 1 hour to dig, we can multiply this by 8 to find the time it would take to dig the larger hole:

1 hour x 8 = 8 hours

So, it would take the landscaper 8 hours to dig a hole 4 feet deep, 4 feet long, and 4 feet wide, assuming everything else remains the same.