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precalculus

the variable j varies jointly as the square of h and as the cube root of a, and it varies inversely as s. What happens to j when h is doubled, a is multiplied by 8, and s is multiplied by 4?

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cody

  1. j = k(h^2)(a^(1/3)/s

    when h is doubled , a multiplied by 8, s multiplied by 4

    j2 = k (4h^2)(2a^(1/3)/(4s)

    j2 / j = [ k (4h^2)(2a^(1/3)/(4s) ] / [k(h^2)(a^(1/3)/s]
    = 4(2)/2 = 2

    the value of j will double

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    Reiny

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