An empty vial has a mass of 56.42 g. If the vial has a mass of 233.13 g when completely filled with liquid mercury (d = 13.53 g/cm3), what is the volume of the vial?

mass = volume x density.

233.13 - 56.42 will give you the mass of mercury. Plug that in for mass, plug in 13.53 for the density, and calculate volume. Check my work. Make sure there are no typos.

convert the following quantities to the required unit.

277 cm to meters

Kala, to get your question answered you need to post a separate question rather than adding to an existing question.

To find the volume of the vial, we can use the formula:

Density = Mass / Volume

Here, we are given the density of liquid mercury (d = 13.53 g/cm^3) and the mass of the vial when it is completely filled with mercury (233.13 g). We are also given the mass of the empty vial (56.42 g).

First, we need to calculate the mass of the mercury that fills the vial. We can subtract the mass of the empty vial from the mass of the filled vial:

Mass of mercury = Mass of filled vial - Mass of empty vial
= 233.13 g - 56.42 g
= 176.71 g

Now, we can use the formula for density to find the volume of the mercury:

Density = Mass / Volume

Rearranging the formula to solve for volume:

Volume = Mass / Density

Substituting the values:

Volume = 176.71 g / 13.53 g/cm^3

Calculating the volume:

Volume = 13.04 cm^3 (rounded to two decimal places)

Therefore, the volume of the vial is approximately 13.04 cm^3.