Two point charges Q1= -25uC and Q2= 50uC are separated by a distsance of 12cm the electric field at the point P is zero how far from Q1 is P?

1.6

Solution

To find the distance from Q1 to point P, where the electric field is zero, we can use the concept of the electric field due to point charges.

The electric field at a point due to a point charge can be calculated using the formula:

E = k * (Q / r^2)

Where:
- E is the electric field
- k is the electrostatic constant (k ≈ 9 x 10^9 N m^2 / C^2)
- Q is the charge
- r is the distance from the charge

In this case, we have a negative charge Q1 = -25 µC and a positive charge Q2 = 50 µC. Since the electric field at point P is zero, the electric fields due to Q1 and Q2 must cancel each other out.

Therefore, we can set up the following equation:

E1 + E2 = 0

Substituting the formula for electric fields, we get:

(k * Q1 / r1^2) + (k * Q2 / r2^2) = 0

Since Q1 is negative and Q2 is positive, we need to consider their signs while calculating the electric fields.

Now, we know that Q1 = -25 µC, Q2 = 50 µC, and the distance between the charges is 12 cm. Let's assume the distance from Q1 to point P is x. Therefore, the distance from Q2 to point P would be 12 - x.

Plugging in these values into the equation, we get:

(k * (-25 x 10^-6) / x^2) + (k * (50 x 10^-6) / (12 - x)^2) = 0

Simplifying the equation, we can solve for x.

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