How many oxygen atoms in 9 grams of sugar?
To determine the number of oxygen atoms in 9 grams of sugar, we need to know the chemical formula of sugar. Common table sugar, or sucrose, has the chemical formula C12H22O11.
To calculate the number of oxygen atoms, we first need to find the molar mass of sugar. We can do this by adding up the atomic masses of its constituent elements. From the periodic table, we find that the atomic mass of carbon (C) is approximately 12.01 g/mol, hydrogen (H) is approximately 1.01 g/mol, and oxygen (O) is approximately 16.00 g/mol.
Next, we multiply the number of atoms of each element in the formula by their respective atomic mass and sum them up:
C: 12 (atoms) * 12.01 (g/mol) = 144.12 g/mol
H: 22 (atoms) * 1.01 (g/mol) = 22.22 g/mol
O: 11 (atoms) * 16.00 (g/mol) = 176.00 g/mol
Now, we add these values together:
144.12 + 22.22 + 176.00 = 342.34 g/mol
This means that the molar mass of sugar is 342.34 g/mol.
To find the number of moles of sugar in 9 grams, we divide the given mass by the molar mass:
9 g / 342.34 g/mol = 0.026 moles
Since the chemical formula of sugar (C12H22O11) indicates that there are 11 oxygen atoms in each molecule, we can multiply the number of moles by Avogadro's number (6.022 x 10^23 molecules/mol) and then by 11:
0.026 moles * (6.022 x 10^23 molecules/mol) * 11 = 1.859 x 10^22 oxygen atoms
So, there are approximately 1.859 x 10^22 oxygen atoms in 9 grams of sugar.
Use a conversion factor.
You need the formula of sugar to solve for it.
9grams 1mol 6.022X10^23 formulaUnits
X _____ X ___________
g of sugar 1mol
...
__Formula units X atoms of oxygen
________________
1formula unit
then you get your answer in atoms of O.