Physics

A ball is thrown from ground level up in the air at 61m/s. How fast is the ball going 1s after being thrown.


This problem wants you to use the formula
v = (-1/2)gt^2 + v_0
g=9.8m/s^2 and v_0 = 61m/s so
v = (-1/2)g*(1s)^2 + 61m/s at t = 1.


I wrote the formula wrong. It should be
v = -gt + v_0

I mixed the velocity formula and the distance formula.


You need the formula: velocity (finall) = velocity (initial) + at.

Here, the velocity initial is 61, and the t (time) is 1s. Remember, since the ball is decelerating (the acceleration is in the oppostie direction to which the ball is thrown), the a is -9.8m/s^2. Just plug 'em in!

  1. 👍
  2. 👎
  3. 👁

Respond to this Question

First Name

Your Response

Similar Questions

  1. college physics

    a tennis ball is thrown straight up with an initial velocity of 22.5 m/s. it is caught at the same distance above the ground. a). how long does it take to reach its maximum height? b). how high does the ball rise? c). at what

  2. science

    a ball is thrown straight upward and returns to the thrower's hand after 3.00s in the air. A second ball is thrown at an angle of 30.0 deg with the horizontal. At what speed must the second ball be thrown so that it reached the

  3. Algebra

    THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the ground h(t) of an object thrown vertically from a height of h0 feet, with an initial velocity of v0 feet per second, if there is no air friction and t is the

  4. Algebra

    A ball is thrown into the air. The height in feet of the ball can be modeled by the equation h = -16t2 + 20t + 6 where t is the time in seconds, the ball is in the air. When will the ball hit the ground? How high will the ball go?

  1. Quadratic equations

    A ball is thrown vertically upwards From the top of a building of height 29.4 m and with an initial velocity 24.5 m/sec. If the height H of the ball from the ground level is given by H = 29.4 + 24.5t - 4.9t², then find the time

  2. Maths

    A ball is thrown vertically upwards at 3 m s-1 from 1m above ground level (I) write down the equation for the height of the ball above the ground after t seconds (while the ball is in the air). (II) use your answer to find the

  3. Physics

    Q.1 A ball is thrown 233 m upward and then falls back to earth. Neglecting air resistance, how long will it be in the air? The acceleration of gravity is 9.8 m/s2 . Answer in units of s. Q.II An object is thrown downward with an

  4. Algebra

    A ball is thrown into the air. The height h, in feet, of the ball can be modeled by the equation h= -16t^2+20t+6, where t is the time, in seconds, the ball is in the air. When will the ball hit the ground? first should I use x=

  1. Physics

    A ball is thrown straight upward and returns to the thrower's hand after 2.30 s in the air. A second ball is thrown at an angle of 42.0° with the horizontal. At what speed must the second ball be thrown so that it reaches the

  2. Physics

    The place kicker on a football team kicks a ball from ground level with an initial speed of 8.30 m/s at an angle of 19.0° above the horizontal. How long is the ball in the air before it lands on the ground again? You may neglect

  3. Physics

    A ball is thrown straight up from the ground with speed v_0. At the same instant, a second ball is dropped from rest from a height H, directly above the point where the first ball was thrown upward. There is no air resistance.

  4. physics

    1)A ball is thrown so that it initially travels at 10ms-1 at an angle of 70 above the horizontal a)a simple model assumes that the ball is thrown from ground level and lands at the samelevel.Find the time of flightand range of the

You can view more similar questions or ask a new question.