Forty-two grams of benzoic acid is treated with concentrated nitric acid in some sulfuric acid. Forty-two grams of the major expected organic product is isolated. What is the percentage yield for this experiment? Give an equation with structural formulas for the major reaction and show your calculations.
Can anyone help? Any help will do. Thanks.
42 g/molar mass benzoic acid = mols benzoic acid
Convert to mols of the product. You need to supply the product.
Convert mols product to grams by mols x molar mass = grams. This is the theoretical yield. The actual yield is 42 grams according to the problem.
%yield = [actual yield/theoretical yield]*100
got it thanks
To find the percentage yield for this experiment, we need to follow a few steps:
1. Calculate the number of moles of benzoic acid:
42 g / molar mass of benzoic acid = moles of benzoic acid
2. Determine the number of moles of the major expected organic product. Unfortunately, the problem does not provide the specific product. Therefore, we cannot proceed with this step without additional information.
3. Convert the moles of the product determined in step 2 to grams by multiplying it by its molar mass to find the theoretical yield.
4. The problem states that the actual yield is 42 grams.
5. Calculate the percentage yield using the formula:
% yield = (actual yield / theoretical yield) * 100
However, without the knowledge of the specific organic product formed in the reaction, it is impossible to proceed with the calculations. Therefore, we need additional information to provide a complete answer with calculations.