This needs to be solved and put in equation form. Seems simple but not sure if I am figuring it right.

Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin does she have?

use the equations and solve
n ---> number of nickels
d ----> number of dimes

0.05n + 0.1d = 3.50

n + d = 50

n ---> number of nickels

d ----> number of dimes

0.05n + 0.1d = 3.50

n + d = 50

25 and 25

To solve the problem and put it in equation form, we can use the given information about Jill's money and number of coins.

Let:
n = number of nickels
d = number of dimes

We are told that Jill has $3.50 in nickels and dimes, which can be expressed as the equation 0.05n + 0.1d = 3.50. Here, 0.05 represents the value of a nickel, and 0.1 represents the value of a dime.

We are also given that Jill has a total of 50 coins, so the sum of the number of nickels and dimes should be equal to 50. This can be expressed as the equation n + d = 50.

Now, we have two equations:
0.05n + 0.1d = 3.50
n + d = 50

To solve this system of equations, we can use substitution or elimination. Let's use substitution in this case.

Rearrange the second equation to solve for n: n = 50 - d.

Substitute this expression for n in the first equation:
0.05(50 - d) + 0.1d = 3.50

Simplify the equation:
2.50 - 0.05d + 0.1d = 3.50
0.05d = 1
d = 20

Now, substitute the value of d back into the second equation:
n + 20 = 50
n = 30

Therefore, Jill has 30 nickels and 20 dimes.