when x=3 and y=5 how much does the value of 3x to the seond power minus 2y to the second power exceed the value of 2x to the second power minus 3y
value=3x^2-2y^2 - 2x^2+3y
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3^2-2*5^2+3(5)
Given
f(x,y) = ((3x)²-(2y)²) - ((2x)²-3y)
Find f(3,5).
f(3,5)
=((3*3)²-(2*5)²)-((2*3)²-3*5)
=(9²-10²)-(6²-15)
=(81-100)-(36-15)
=-19-21
=-40
Please check if the interpretation of the question is correct.
To find the value of each expression, let's start by substituting the given values of x and y into each expression:
For 3x² - 2y²:
When x = 3 and y = 5:
3(3)² - 2(5)²
= 3(9) - 2(25)
= 27 - 50
= -23
For 2x² - 3y:
When x = 3 and y = 5:
2(3)² - 3(5)
= 2(9) - 3(5)
= 18 - 15
= 3
Now, to find how much 3x² - 2y² exceeds 2x² - 3y, we subtract the value of the second expression from the first expression:
-23 - 3
= -26
Therefore, the value of 3x² - 2y² exceeds 2x² - 3y by -26.