If Z is a standard deviation, find the probability that Z lies between -1.10 and -0.36
You have not provided enough information to answer that question. Besides, a different symbol should be used for the standard deviation and the variable (Z) itself. Are you sure there isn't a "sigmaZ", or something like that, in the statement of the standard deviation?
Oops! made a typing error. It should read: If Z is a standard normal variable, find the probability that Z lies between -1.10 and -0.36
See my answer in your repost of this question.
Thanks for asking.
Sorry, it is the same problem posed by John. Is that also you?
Yes, that is correct. I apologize for the confusion. I will provide you with the explanation again.
To find the probability that a standard normal variable Z lies between -1.10 and -0.36, you can use a standard normal table or a calculator that has the capability to compute probabilities for the standard normal distribution.
Here is how you can use a standard normal table:
1. Locate the first value, -1.10, in the leftmost column of the table. This represents the z-score.
2. Move across the row to find the second value, -0.36, in the top row of the table. This also represents the z-score.
3. The intersection of the row and column is the probability corresponding to the range between -1.10 and -0.36.
If you are using a calculator, you can use the cumulative probability function for the standard normal distribution. The cumulative probability function represents the area under the standard normal curve to the left of a given z-score.
Using a calculator, you can find the probability by calculating the cumulative probability of -0.36 and subtracting from it the cumulative probability of -1.10:
P(-1.10 < Z < -0.36) = P(Z < -0.36) - P(Z < -1.10)
This will give you the probability that Z lies between -1.10 and -0.36.
I hope this helps!