(x)/(x^2-4)

State the y-intercept. Would the y-intercept be (0,0)? or just 0?

State the vertical asymptote(s). Would the vertical asymptotes be x = -2, x = 2

State the horizontal asymptote. Would that be 0 as well?

The y intercept is a point, and so (0,0) accurately expresses it.

The vertical asymptotes are correct.

The horizontal asymptote is 0 because the power of x in the numerator is less than the power of x in the denominator.

The horizontal asymptote is the limit as x--> infinity of x/(x^2-4).

Dividing by x/x, we get limit as x--> infinity of 1/(x-4/x). 4/x in the denominator approaches 0 as x approaches infinity, so you are left with limit as x--> infinity of 1/x, which also approaches 0 as x --> infinity