Based on the force vector that is hown, I have to determine the x and y vector components.
|\
fy=?| \ f= 200 lb
| \
|___\
fx=?
How do I do this with only one side given and the given 90 degree angle
See comment to the previous post.
There is a right traingle. The hypotenuse has a value of 200 lb I have to find the two other sides of fx and fy. How do i do that with only one side given.
You also need to kmnow one of the angles besides the right angle
To determine the x and y vector components when you have only one side given and a right angle, you can use trigonometric functions.
In this case, since you have the force vector (f) and it forms a right angle with the y-axis, you can determine the y-component (fy) and the x-component (fx) using the trigonometric functions sine and cosine.
The sine function relates the opposite side to the hypotenuse of a right-angled triangle, while the cosine function relates the adjacent side to the hypotenuse. In this case, the force vector (f) is the hypotenuse, and the x and y vector components are the adjacent and opposite sides, respectively.
To find the y-component (fy), you can use the sine function:
sin(θ) = opposite/hypotenuse
sin(90°) = fy/200 lb
Since sin(90°) is equal to 1, we have:
1 = fy/200 lb
Solving for fy, we get:
fy = 200 lb
To find the x-component (fx), you can use the cosine function:
cos(θ) = adjacent/hypotenuse
cos(90°) = fx/200 lb
Since cos(90°) is equal to 0, we have:
0 = fx/200 lb
Solving for fx, we get:
fx = 0 lb
Therefore, the y-component (fy) is 200 lb, and the x-component (fx) is 0 lb.