could someone please help me with these problems i am having trouble.
If y=36 when x =6 find x when y = 42
If y=-18 when x=6 find x when y=6
If y =12 when x= 15 find x when y =21
If y=-6.6 when x=9.9 find y when x =6.6
If y=6 when x=(2/3)find x when y=12
those are the problems you don't have to do all just at least show me step by step how you arrived at the answer thank you so much for helping
take the first one:
y1/y2 = x1/x2
y1=36 x1 is 6
y2=42 x2 is ?
then
36/42=6/x solve for x
and
x=42*6/36 =7
check my thinking.
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These are proportion problems
(1) 6:36=x:42 Which is the same as (6*42)/36=x
(2)6:18=x:6 Which is the same as (6*6)/18=x
(3) 15:12=x:21 I think you can do them now
(4)9.9:-6.6=6.6:y Watch where the y is located here.
(5)(2/3):6=x:12 Be sure to handle the fraction correctly.
In general, a proportion is two ratios a:b=c:d
a and d are called the extremes and b and c the means.
The fundamental relation is a*d=b*c The product of the extremes = the product of the means.
You can also think of it in terms of fractions a/b = c/d. in terms of fractions both ratios are different names for the same fraction. One is a multiple of the other. In the first one we have
6:36 or 6/36=1/6
We want to find x such that x/42 = 1/6 so x=42*(1/6)
You can verify that 1/6 = 6/36 = 7/42.
The fraction 1/6 would be the fraction in lowest terms in integers. In some places finding that lowest reducible integer fraction is very important. Other times we can't find such an integer ratio, e.g. if the numbers are irrational.
If y =12 when x= 15 find x when y =21
y=kx 21
To find the value of x when y is equal to 21, we need to first determine the value of k, which is the constant of proportionality.
Given that y = 12 when x = 15, we can use this information to solve for k:
12 = k * 15
To isolate k, divide both sides of the equation by 15:
k = 12/15
Simplifying, we find:
k = 4/5
Now that we know the value of k, we can use it to find x when y = 21:
21 = (4/5) * x
To solve for x, we need to isolate it on one side of the equation. Multiply both sides by 5/4:
(5/4) * 21 = x
Simplifying the expression:
105/4 = x
Therefore, x is equal to 105/4 when y is equal to 21.