Let x = log_2 1/8
Write the exponential form of the equation and solve the equation for x.
Does this work? Thanks!
Exponential form is 2^-3=1/8
To Check:
2^-3=1/2^3=1/8
Please continue with post below, you are almost there!
http://www.jiskha.com/display.cgi?id=1249473232
x = log_ 2 2^-3
? I am lost now. I really thought I had it from what I just posted.
Exponential form is 2^-3 = 1/8 This isn't correct?
To Check:
2^-3=1/2^3=1/8
Exponential form is 2^-3 = 1/8 This isn't correct?
This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding.
You also need to do the second part: " and solve the equation for x."
You are very close to finishing, keep it up.
Solve for x i got, the exponential is the problem for me...Here is what i got for x.
To Solve:
1/8=8^-1
8=2^3
1/8=2^3^-1=8^-1
=2^-3
Log_2 1/8 = log_2 2^-3
=-3log_2 2
x =-3
To Check:
2^x=1/8= 2^-3
x=-3
Correct!
Now what about the Exponential form
?
2^-3 = 1/8 This isn't correct? If not then how do i show Let x = log_2 1/8 in exponential form?
"Algebra Help - MathMate, Wednesday, August 5, 2009 at 6:41pm
Exponential form is 2^-3 = 1/8 This isn't correct?
This part is correct, that's the "so far so good" part. Sorry if there was a misunderstanding. "
The exponential form has to be correct for you to proceed with the second part, otherwise the second part will not be correct.
Thank you this really helps! So I got
Exponential form is 2^-3 = 1/8
and To solve x = -3 So this is all of it?
That's all there is to it.
If you have time, read up and understand of the identities listed earlier. You'll be glad you did when exam comes around.