a combination lock has three dials, each numbered from 1-9. each combination consists of 3 digits, one from each dial. how many different combinations are possible?
please help me i tried this for 10 mins i cant figure it out. thanks
what do you mean whats wrong with it?...
are you saying that's how to figure out the answer? so 9 multiplied by 9 multiplied by 9?
yes. 9*9*9 is the answer. :D
To find the number of different combinations possible for a combination lock with three 9-dial dials, you can use the concept of permutations.
Since you have three dials and each dial has 9 possible numbers (1-9), you can choose a number from the first dial in 9 ways, a number from the second dial in 9 ways, and a number from the third dial in 9 ways.
To find the total number of combinations, you need to multiply the number of choices for each dial. In this case, it would be 9 choices for the first dial, multiplied by 9 choices for the second dial, multiplied by 9 choices for the third dial.
So, the total number of combinations possible would be 9 x 9 x 9 = 729.
Therefore, there are 729 different combinations possible for the given combination lock.