A transformer has a secondary voltage of 12 V. The primary voltage is 60V. The number of turns in the secondary is 100. How many turns are in the primary?
I keep getting 200 using the equation Vs/Vp= Ns/Np
the answer is 500... what am i doing wrong
I don't know about the equation but if the secondary is 12 and primary is 60, then the primary must have more turns. If the secondary is 100 turns, then we multiply 100 x factor and the factor must give us a number higher than 100, so that is 60/12.
100 x (60/12) = 500 turns.
Using the formula,
Vs=12
Vp=60
Ns=100
Np = ?
(12/60) = (100/x)
and that gives me
12x = 60*100=60,000
x = 60,000/12 = 500
You must not be solving the proportion correctly.
Thanks that helps alot i don't know why i was using 24 for Vp
You actually made a mistake while using the equation. The correct formula to use is:
Vs/Vp = Ns/Np
Where:
Vs = Secondary voltage
Vp = Primary voltage
Ns = Number of turns in the secondary
Np = Number of turns in the primary
So, in this case:
12V/60V = 100/Np
Now, let's solve for Np:
12V/60V = 100/Np
To simplify the equation, we can multiply both sides by 60V:
12V * 60V / 60V = 100 * 60V / Np
12V = 6000V / Np
Now, to isolate Np, we can cross-multiply:
12V * Np = 6000V
Np = 6000V / 12V
Np = 500
Therefore, the number of turns in the primary is 500, not 200.
To find the number of turns in the primary coil of a transformer, you can use the formula:
Vs/Vp = Ns/Np
Where:
Vs is the secondary voltage (12V),
Vp is the primary voltage (60V),
Ns is the number of turns in the secondary coil (100), and
Np is the unknown number of turns in the primary coil.
Using this formula, you can rearrange it to solve for Np:
Np = (Vs/Vp) * Ns
Plugging in the given values:
Np = (12/60) * 100
Doing the calculations:
Np = 0.2 * 100
Np = 20
Therefore, according to the calculation, the number of turns in the primary coil should be 20, not 500.
If you keep getting an answer of 200, it suggests that there may be an error in your calculations. Double-check your calculations and ensure that you are dividing the secondary voltage by the primary voltage (not the other way around).