A loop wire is in a magnetic field of 2T. What is the magnitude of the magnetic flux?

0.2 m
B = 2T
30 degrees
and n is pointing out of the page

I know you do BAcos(30) but im not getting the right answer... what am i doing wrong

That is the correct formula if 30 degrees is the angle between the B field and the "surface normal" vector n. Is 0.1m the radius or the diameter of the loop?

We cannot find the error in your work unless you show it.

To calculate the magnitude of the magnetic flux through a loop wire in a magnetic field, you can use the formula:

Φ = B * A * cos(θ)

Where:
Φ is the magnetic flux,
B is the magnetic field strength,
A is the area of the loop wire, and
θ is the angle between the magnetic field and the normal vector of the loop wire.

In this case, you are given:
B = 2T (magnetic field strength),
A = 0.2m (area of the loop wire), and
θ = 30 degrees (angle between the magnetic field and the normal vector of the loop wire).

To calculate the magnitude of the magnetic flux, plug these values into the formula:

Φ = 2T * 0.2m * cos(30 degrees)

Step 1: Convert the angle from degrees to radians:
θ_rad = 30 degrees * (π/180 degrees)

Step 2: Calculate the cosine of the angle:
cos(θ_rad) = cos(30 degrees) ≈ 0.866

Step 3: Substitute the values into the formula:
Φ = 2T * 0.2m * 0.866

Step 4: Calculate the magnitude of the magnetic flux:
Φ ≈ 0.346 T • m²

Therefore, the magnitude of the magnetic flux through the loop wire is approximately 0.346 T • m².