F=n/15, where n is the total amount of credits in which students enroll for a given semester. If students on a campus register for a total of 52425 credits, how many full-time equivlant students does the campus have? Solve the formula for n. N=

I do not know if you paraphrased the question, but some definitions seem to be missing.

I would interpret the question as also saying assuming each full time student registers for 15 credits, and the function
F(n)=n/15 represents the number of full-time equivalent students for a total registered credits of n.

If these assumptions are correct, you would "plug-in" n=52425 into the given function to obtain the number of full-time equivalent students.

Yeah, I think I need to re-think on this one and decipher what is being said in order to resolve ... ty:)

To solve the formula F = n/15 for n, you need to isolate the variable n. Here's how you can do it:

Step 1: Start with the formula F = n/15.

Step 2: Multiply both sides of the equation by 15 to eliminate the denominator:

15 * F = n/15 * 15

This simplifies to:

15F = n

Now, you have solved the formula for n. The value of n is 15F.

To find the number of full-time equivalent (FTE) students for a given campus, you need to substitute the value of n into the equation.

Given that the total amount of credits enrolled by students on the campus is 52425, you can substitute this value for n:

n = 52425

Now, substitute the value of n into the equation:

15F = 52425

To find F, the number of full-time equivalent students, you need to isolate F. Here's how:

Step 1: Divide both sides of the equation by 15:

(15F)/15 = 52425/15

This simplifies to:

F = 3495

Therefore, the campus has 3495 full-time equivalent (FTE) students.