A bridge is ten meters above a canal and A motor boat going 3minutes per second passes under the center of the bridge at the same time instant that a woman walking 2minutes per second reaches that point and How rapidly are they separating 3seconds later"

To find out how rapidly the boat and the woman are separating 3 seconds later, we need to first determine the positions of the boat and the woman at the starting time and after 3 seconds.

Let's define the variables:
- Let x represent the horizontal distance covered by the woman from the bridge center in meters.
- Let y represent the horizontal distance covered by the boat from the bridge center in meters.

At the starting time (t = 0), the boat passes under the center of the bridge, so y = 0. The woman is walking towards the bridge center, so x = 0.

Since the boat is traveling at a constant speed of 3 meters per second, after 3 seconds (t = 3), the boat covers a horizontal distance of 3 * 3 = 9 meters from the bridge center. Therefore, y = 9.

Similarly, since the woman is walking at a constant speed of 2 meters per second, after 3 seconds (t = 3), the woman covers a horizontal distance of 2 * 3 = 6 meters from the bridge center. Therefore, x = 6.

Now, we can calculate the separation between the boat and the woman after 3 seconds:

Separation = distance covered by the boat - distance covered by the woman
= |y - x|
= |9 - 6|
= 3 meters

Therefore, the boat and the woman are separating at a rate of 3 meters per 3 seconds, which simplifies to 1 meter per second.