I had to create a word problem. My final result was 8 < 8.56 but I am not sure how to graph it. I know you can't show graphs on this site but can you give pointers?
8 < 8.56 is an obvious statement of fact. I don't see how it can be the result of a word problem. On a graph, you'd just have a line representing value of x. 8 would be to the left of 8.56
I started off with 336 + 25s < 550
s stands for students
In that case, the solution is
25 s < 214
s < 8.56
Whatever your word problem is, any value of s less than 8.56 will satisfy it. You don't need a graph to illustrate that.
It would help us if you stated the original word problem that led to that answer.
Sure....I'll show what has been requested and my scenario. I just wasn't sure how I was supposed to graph it. (shaded area)
The Science instructor estimates that a group of students (on a hiking expeditin) can carry less than 550lbs of food and equipment. The group must carry 336lbs of equipment as well as 251lbs of food for each student. What is the greatest possible number of students on the field trip?
336lb + 25lbs times numer of students is less than 550lbs
s=students
336 + 25s < 550
336 + 25s - 336< 550 -0336
25s < 214
25/25 < 214/25
s < 8.56
The greatest number of students in the field trip is 8
equipment plus the food is less than 550lbs
OK, I see how your answer came from a word problem. I think you typed 251 lbs when you meant 25 lb. Since the number of students must be an integer, it is correct to say the answer is 8 or less.
Something other than the students must be carrying and limiting the amount of the food and equipment. Perhaps they are using a certain number of pack animals or a small boat. Otherwise, numbers of students smaller than 8 would have an even harder time carrying the 550 lb.
As far as a graph is concerned, but show a line from 0 to 10 (or higher) with a heavy line going from 0 to 8.56. Integers in that range are potential answers. (1 through 8)
You are right....I need to decrease the amounts. I still don't fully understand how to shade. I understand that I need to shade from 0 to 8.56 but do I shade from 0 on the right side of x to any point on the right and up to 8.56? also not below the x line....sorry..... I just learned how to plot but now need to get this concept. Thank you for your help....
No problem! I can help clarify how to shade the graph. In this case, since we are dealing with the inequality s < 8.56, we want to shade the area that represents all the possible values of s that satisfy this inequality.
To shade the graph, you would start at 0 on the number line and then shade everything to the left of the number 8.56. This means you would shade from 0 all the way up to 8.56, but not including 8.56 itself.
So, you would shade the area from 0 to 8 without including 8 itself. This represents all the possible whole number values of the variable s that satisfy the inequality s < 8.56.
I hope this clarifies how to shade the graph for you! Let me know if you have any more questions.
No problem! I'm here to help clarify. When shading, you want to shade the region that satisfies the inequality. In this case, the inequality is "s < 8.56".
To shade the region, you'll want to shade everything to the left of 8.56 on the number line. Since s represents the number of students, you'll shade to the left of 8.56.
So, you would shade the region starting from 0 and extending leftwards until just before 8.56 (since it's a strict inequality: s < 8.56). Make sure not to shade below the x-axis since the number of students cannot be negative in this scenario.
By shading this region, you are indicating that any value of s that falls within the shaded region (less than 8.56) would be a valid solution.
I hope this clarifies the concept of shading for you! Let me know if you have any more questions.