Which would be the inverse of this:

Let f(x)=(x+3)(2x-5)

f^ (-1) x = (5x - 3)/ (2x + 1)

f^ (-1) x = (5x + 3)/ (2x - 1)

Could you check if there wasn't a typo, namely,

"Let f(x)=(x+3)/(2x-5)... "
If that's the case, it's the second response.
To double check,
let g(x)=f-1(x)=(5x+3)/(2x-1)
Evaluate
f(g(x))
= ((5x+3)/(2x-1)+3)/((2(5x+3))/(2x-1)-5)
= x

Let y = f(x)

y = (x + 3)/ (2x - 5)

Switch x and y.

x = (y + 3)/ (2y - 5)

Multiply both sides by (2y - 5).

2xy - 5x = y + 3

Subtract 3 from both sides.

2xy - 5x - 3 = y

Subtract 2xy from both sides.

-5x - 3 = -2xy + y

Factor the right side.

-5x - 3 = y (-2x + 1)

Divide both sides by (-2x + 1).

(-5x - 3)/ (-2x + 1) = y

(5x - 3)/ (2x + 1) = y

Now we replace y with the inverse function notation: f^ (-1) x.

f^ (-1) x = (5x + 3) / (2x - 1)

This my work to reflect the answer. Is it correct? Thanks!

Yes, the calculation is correct.

Note: You may not have noticed that you omitted the division sign in the initial post.

Thanks for pointing that out!

You're welcome!

To find the inverse function of f(x) = (x+3)(2x-5), we need to switch the roles of x and y in the equation and solve for y.

Step 1: Write the original equation:
f(x) = (x+3)(2x-5)

Step 2: Replace f(x) with y:
y = (x+3)(2x-5)

Step 3: Swap x and y:
x = (y+3)(2y-5)

Step 4: Solve for y:
Expand the equation:
x = 2y^2 - 5y + 6y - 15
x = 2y^2 + y - 15

Rearrange the equation:
2y^2 + y - 15 - x = 0

Step 5: Apply the quadratic formula:
The quadratic formula states that for an equation of the form ax^2 + bx + c = 0, the solution for x is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)

Applying this formula to our equation, where a = 2, b = 1, and c = -15, we can solve for y:

y = (-1 ± √(1^2 - 4(2)(-15))) / (2(2))
y = (-1 ± √(1 + 120)) / 4
y = (-1 ± √121) / 4

Simplifying further:
y = (-1 ± 11) / 4

This gives two possible values for y:
y = (-1 + 11) / 4 = 10/4 = 2.5
y = (-1 - 11) / 4 = -12/4 = -3

Step 6: Write the inverse function:
Now that we have the values of y, we can write the inverse function.
f^(-1)(x) = 2.5 or f^(-1)(x) = -3

Therefore, the inverse of f(x) = (x+3)(2x-5) is f^(-1)(x) = 2.5 or f^(-1)(x) = -3.