what volume of 0.4 M HCl is required to neutralize

what volume of 0.4 M HCl is required to neutralize 100.0 mL of 0.3 M LiOH?

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  1. For a 1:1 ratio of acid to base, which you have, mL x M = mL x M.
    mL(HCl) x 0.4 M = mL(LiOH) x 0.3 M
    Solve for mL(HCl).

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  2. (ii) If 22.0 mL of 2.5 M HCl was used to neutralize 50.0 mL of a Ba(OH)2 solution, what was the concentration of the base?

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  3. 75 ml of hcl

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  4. 0.6

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