1)Solve the matrix:[2x] [14]for x
[3y]=[12]
answer=7
2)V[3 1]
[0 2]
[-4 5].The dimensions of matrix V.
answer=3x2
3)The first row of T+U
T[4 -5 2] U[-9 6 4]
[8 -1 3] [-5 -2 3]
answer=[-5 1 6]
4)The first row of V-T.
V[3 1] T[4 -5 2]
[0 2] [8 -1 3]
[-4 5]
answer=not possible
1) Did you leave out an = sign between 2x and 14? If so, they are scalar matrics and 2x = 14, so x = 7. I have no idea what you also have 3y = 12
2. Yes, V has three row ans two columns.
3. correct
4. correct. You cannot subtract matrices of unequal dimensions.
its suppose to be
Solve the matrix:[2x] [14]for x
[3y]= [12]
well its still not posting right but the 3 is under the 2 and the 12 is under the 14
The matrix
2x..14
3y..12
is just an arrangement of 4 numbers. You have not set it equal to anything else, so I don't know what you mean by "solving" it for x. I also don't understand the meaning of your bracket symbols. Is is supposed to denote a determinant?
Because of the limited graphic capability here, and a shortage of available qualified staff, Jiskha is probably not a suitable place to get help with matrix problems.
thats the way my book has it.theyre in brackets.but that's basically the idea,could you look over my other problems for me?
Sure, I can help you with the other problems. Let's go through them one by one:
1) Solve the matrix: [2x] [14] for x
[3y] [12]
It seems like you are trying to solve a system of equations given by this matrix equation. To solve for x and y, we can express the given matrix equation as a system of equations:
2x = 14 (Equation 1)
3y = 12 (Equation 2)
To solve Equation 1, we can divide both sides of the equation by 2:
2x/2 = 14/2
x = 7
Similarly, to solve Equation 2, we divide both sides by 3:
3y/3 = 12/3
y = 4
So, the solution to the system of equations is x = 7 and y = 4.
2) V = [3 1]
[0 2]
[-4 5]
To find the dimensions of matrix V, we count the number of rows and columns. In this case, matrix V has 3 rows and 2 columns. So, the dimensions of matrix V are 3x2.
3) The first row of T+U
T = [4 -5 2] U = [-9 6 4]
[8 -1 3] [-5 -2 3]
To find the sum of matrices T and U, we add the corresponding elements of each matrix. The result will be a matrix with the same dimensions as T and U. Adding the matrices, we get:
T + U = [ (4 + (-9)) (-5 + 6) (2 + 4) ]
[ (8 + (-5)) (-1 + (-2)) (3 + 3) ]
Simplifying the addition, we have:
T + U = [ -5 1 6 ]
So, the first row of T + U is [-5 1 6].
4) The first row of V - T
V = [3 1] T = [4 -5 2]
[0 2] [8 -1 3]
[-4 5]
To subtract matrices V and T, we subtract the corresponding elements of each matrix. However, for matrices to be subtracted, they must have the same dimensions. In this case, matrix V has dimensions 2x2 (2 rows and 2 columns), while matrix T has dimensions 3x3. Since the matrices have different dimensions, we cannot perform the subtraction operation.
Therefore, it is not possible to find the first row of V - T in this case.