# Pre Calculus

The burial cloth of an Egyptian mummy is estimated to contain 56% of the carbon-14 it contained originally. How long ago was the mummy buried? (the half-life of carbon-14 is 5730). Please round the answer to the nearest tenth. I have figured that:

m(t) = Moe(-ln2/5730) is a starting point

1. Let
P14 = fraction of C14 found in sample (0.56)
T1/2 = radioactive half life (5730 years)
Then
Age of sample
=T1/2*(ln(P14)/ln(0.5)) (Before present)
=5730*(ln(0.56)/ln(0.5)) (BP)
=4793 (BP)

posted by MathMate

## Similar Questions

1. ### Precalculus

The burial cloth of an Egyptian mummy is estimated to contain 57% of the carbon-14 it contained originally. How long ago was the mummy buried? (The half-life of carbon-14 is 5730 years.)
2. ### Precalculus

The burial cloth of an Egyptian mummy is estimated to contain 57% of the carbon-14 it contained originally. How long ago was the mummy buried? (The half-life of carbon-14 is 5730 years.)
3. ### PreCalculus

The half life of Carbon-14 is 5730 years. a. find the rule of the function that gives the amount remaining from an initial quantity of 100 milligrams of carbon14 after t years. b. the burial cloth of an egyptian mummy i sestimated
4. ### social studies

Your answers are in these websites. http://dictionary.reference.com/browse/relief http://www.virtual-egyptian-museum.org/Collection/FullVisit/Collection.FullVisit-JFR.html?../Content/STO.XL.00528.html&0 (Broken Link Removed)
5. ### Chemistry

The cloth shroud from around a mummy is found to have a carbon-14 activity of 8.1 disintegrations per minute per gram of carbon as compared with living organisms that undergo 15.2 disintegrations per minute per gram of carbon.
6. ### sociol studies

The spells interred with Egyptian mummies came from the Book of the Dead. For more information, check this site. http://www.crystalinks.com/egyptafterlife.html What is the collection of spells that was buried with mummy? Any
7. ### science

if a egyptian mummy has 61% carbon-14 how long ago was it buried? Take a 100 g initial sample. Now there are 61 g C-14. Use ln(No/N) = kt where No = 100 N = 61 You will need k and you may obtain that from k = 0.693/t1/2. Look up