Pre Calculus

The burial cloth of an Egyptian mummy is estimated to contain 56% of the carbon-14 it contained originally. How long ago was the mummy buried? (the half-life of carbon-14 is 5730). Please round the answer to the nearest tenth. I have figured that:

m(t) = Moe(-ln2/5730) is a starting point

asked by Shellie
  1. Let
    P14 = fraction of C14 found in sample (0.56)
    T1/2 = radioactive half life (5730 years)
    Then
    Age of sample
    =T1/2*(ln(P14)/ln(0.5)) (Before present)
    =5730*(ln(0.56)/ln(0.5)) (BP)
    =4793 (BP)

    posted by MathMate

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