If I were to use dichromate and add HCL and Ba(NO3)2 and NaOH , what should form?
Im thinking the Ba(NO3)2 would still form a precipitate but im not too sure about everything else
Answered below.
To predict the products of a chemical reaction, you need to know the chemical formulas and the principles of reaction types. Let's break down the reaction you mentioned and determine the products step by step.
1. Dichromate (Cr2O7^2-) reacts with hydrochloric acid (HCl):
- The dichromate ion (Cr2O7^2-) is a strong oxidizing agent and can react with HCl.
- The reaction can be represented as: Cr2O7^2-(aq) + 14HCl(aq) → 2CrCl3(aq) + 7H2O(l) + 3Cl2(g)
- As a result, chromium(III) chloride (CrCl3), water (H2O), and chlorine gas (Cl2) are formed.
2. Chromium(III) chloride (CrCl3) reacts with barium nitrate (Ba(NO3)2):
- The reaction between a metal chloride and a metal nitrate usually results in the formation of an insoluble product called a precipitate.
- The balanced equation for this reaction is: 3Ba(NO3)2(aq) + 2CrCl3(aq) → 2Cr(NO3)3(aq) + 3BaCl2(s)
- As a result, chromium(III) nitrate (Cr(NO3)3) remains in the solution, while barium chloride (BaCl2) precipitates out.
3. Finally, the resulting solution (containing chromium(III) nitrate) is treated with sodium hydroxide (NaOH):
- When a solution containing a metal cation is mixed with a solution containing hydroxide ions, a precipitation reaction can occur.
- The balanced equation for this reaction is: Cr(NO3)3(aq) + 3NaOH(aq) → Cr(OH)3(s) + 3NaNO3(aq)
- As a result, chromium(III) hydroxide (Cr(OH)3) precipitates out, while sodium nitrate (NaNO3) remains in the solution.
So, in summary, the reaction you described would result in the formation of chromium(III) chloride (CrCl3), chlorine gas (Cl2), barium chloride (BaCl2), chromium(III) nitrate (Cr(NO3)3), chromium(III) hydroxide (Cr(OH)3), and sodium nitrate (NaNO3).