solve by the substitution method.

5x + 7y= -19
x=4-4y

what is the solution of the system?

Put x=4-4y in the first equation to get

5(4-4y) + 7y = -19
20 - 20y + 7y = -19
-13y = -39
y=3
Now you can substitute y = 3 in the second equation to get the value of x.

so for x = 5 that's the answer i got.

Try again with

x
=4-4y
=4-4(3)
=4-12
=-8

To solve the given system of equations by the substitution method, we need to solve one equation for one variable and substitute it into the other equation. Let's solve the second equation for x:

x = 4 - 4y

Now we can substitute this value of x into the first equation:

5(4 - 4y) + 7y = -19

Now, simplify the equation:

20 - 20y + 7y = -19

Combine like terms:

20 - 13y = -19

Next, isolate the variable y by moving constant terms to the other side:

-13y = -19 - 20

-13y = -39

Finally, solve for y by dividing both sides by -13:

y = (-39) / (-13)

y = 3

Now, substitute the value of y back into the second equation to find the value of x:

x = 4 - 4(3)

x = 4 - 12

x = -8

Therefore, the solution to the system of equations is x = -8 and y = 3.