Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per huors and train B is traveling at 110 miles per hours. Train A passes a station at 1:100pm if train B passes the same station at 1:22 pm at what time will train B catch up to train A?

Question

Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 100 miles per huors and train B is traveling at 110 miles per hours. Train A passes a station at 1:100pm if train B passes the same station at 1:22 pm at what time will train B catch up to train A?

when will Train B catch up with train A?

Answer 1

Train A passes the station at 13:00 and train B passes at 13:22. Train A has a headway of 22 minutes, which translates into 100 mph*22/60 = 36.67 miles

Speed of train B exceeds that of train by (110-100)=10 mph.
Therefore time to catch-up
= 36.67/10 *60 minutes
= 220 minutes after 13:22
Therefore time when train B catches up with train A
= 13:22 + 220 minutes
= 17:02

Answer 2

Question on Train A should be 13:10 does this change the equation.

Please help

Answer 3

Yes, it does. Sorry.

Could you figure out along the lines of my solution and post your results for checking, if you wish?

Answer 4

so A=13:10

B=13:22
100mph *12/.60= 20miles
(110-100)=10mph
=20/10*60
120 after 13:22

I'm lost after that
=13:22+120
=

Answer 5

It's 120 minutes after 13:22, or

13:22 + 2:00
= 15:22

Answer 6

To determine when Train B will catch up with Train A, we need to calculate the time difference between when Train A passes the station and when Train B passes the station.

We know that Train A passes the station at 1:00 pm, and Train B passes the same station at 1:22 pm. Therefore, the time difference is 22 minutes (1:22 pm - 1:00 pm).

Now, we need to figure out how much distance Train B covers in this 22-minute time difference.

Train A is traveling at 100 miles per hour, and Train B is traveling at 110 miles per hour. The relative speed of Train B with respect to Train A is 110 mph - 100 mph = 10 mph.

Since Train B is traveling 10 miles per hour faster than Train A, we can calculate the distance it covers in 22 minutes:

10 miles/hour * (22 minutes / 60 minutes) = 3.67 miles

Therefore, Train B will catch up to Train A after covering a distance of 3.67 miles.

To determine the time it takes Train B to travel this distance, we can use the formula:

time = distance / speed

time = 3.67 miles / 110 miles/hour = 0.033 hours

Converting hours to minutes:

0.033 hours * 60 minutes/hour = 1.98 minutes

So, Train B will catch up to Train A approximately 1.98 minutes after it passes the station. Therefore, Train B will catch up to Train A at approximately 1:24 pm.