Find b^2 - 4ac and the number of real solutions to equation.
-3x^2+7x=0
The equation is in the form
ax^2 + bx + c = 0
-3x^2 + 7x = 0
So, a = -3, b = 7, and c = 0
b^2 - 4ac = 49 - 0 = 49
The square root of a positive number is a real number, so there are 2 real solutions by the quadratic formula.