Algebra

There are two solutions to | 16x - 5 | = 3. The greatest solution is ___.

Since the expression, 16x - 5, can be either positive or negative, solve for both.

16x - 5 = 3

16x = 8

x = .5

-(16x - 5) = 3

-16x + 5 = 3

-16x = -2

x = 1/8

You can decide which is "greatest."

I hope this helps. Thanks for asking.

  1. 👍 0
  2. 👎 0
  3. 👁 234
asked by Juri
  1. 29239

Respond to this Question

First Name

Your Response

Similar Questions

  1. CountIblis, can i bother you

    Countiblis, i know that you might be busy do you mind if i ask you the following for help.Only if you can please. can you explain to me just one more thing so i can undestand it. Now i have an equation which is : 3x = 3x + 5 which

    asked by jasmine20 on January 3, 2007
  2. Math .

    3(4x - 2) = 2(6x - 3) one solution infinite solutions ** no solution a+5 = 1/5(5a + 25) one solution infinite solutions no solution ** 3(4x - 3) - 7x = 5x - 9 one solution infinite solutions no solution 8+2(8x - 6) (choose all

    asked by Tii on September 30, 2014
  3. algebra

    Solve the system by addition or substitution. 16x-4y=20 y=4x-4 I ask for help with this and forgot to add the problem. can anyone help me understand how to do this? 16x-4y=20 -4x+y=-4 ___________ 16x-4y=20 (4)(-4x+y=-4)

    asked by struggling on May 26, 2007
  4. Math check

    Decide whether each equation has one, no solutions, or infanatly many solutions 1.) 2(x - 3) = 2x One solution no solutions many solutions infinatly many solutions 2.) 3(y - 3?) = 2y - 9 + y One solution no solutions many

    asked by Josh on January 8, 2014
  5. Algebra

    Consider the equation 4x^2 – 16x + 25 = 0. (a) Show how to compute the discriminant, b^2 – 4ac, and then state whether there is one real-number solution, two different real-number solutions, or two different imaginary-number

    asked by Pamela on July 7, 2009
  6. Algebra

    Consider the equation: 4x^2 – 16x + 25 = 0 (a) Show how to compute the discriminant, b^2 – 4ac, and then state whether there is one real-number solution, two different real-number solutions, or two different imaginary-number

    asked by Tammie on July 8, 2009
  7. Math

    5(-3x - 2) - (x - 3) = -4(4x + 5) + 13 Answer Multiply factors. -15x - 10 - x + 3 = -16x - 20 +13 Group like terms. -16x - 7 = -16x - 7 Add 16x + 7 to both sides and write the equation as follows 0 = 0

    asked by Andrew on January 30, 2012
  8. Math

    I sent this in a little while back but the file got corrupted and I have to re do it and I forgot the answer please if it is not done today I fail the year. Simplify the polynomial 16x^2 + 2 + 2x - 15x^2 - 1 + 14x A:31x^2 + 16x +

    asked by Random on June 6, 2016
  9. math

    Decide whether the each equation has one solution, no solutions,or infinitely many solutions. 1. 2(x-3)= 2X A.One solution B.No solutions C.Infinitely many solutions 2. 3(y-3)= 2y-9+y A.One solution B.No solutions C.Infinitely

    asked by jake on December 17, 2014
  10. Pre-Algebra

    1. 16x^2 + 2 + 2x - 15x^2 - 1 + 14x A. 31x^2 + 16x + 1 B. x^2 - 12x + 1 **** C. x^2 + 16x + 1 D. x^2 + 16x + 2 2. 2x^2 + 8 - 4x + 3x - 6x^2 + 7 A. -8x^2 - 7x + 15 B. -4x^2 - x + 15 **** C. 4x^2 + x + 15 D. 8x^2 + 7x + 15 3. 4x^2 +

    asked by Help ASAP on May 10, 2018

More Similar Questions