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Algebra
x/(x3)4(2x5)/(x+2) If the problem is this: x/(x  3)  4  (3x  5)/(x + 2) ...find a common denominator to start. The common denominator is (x  3)(x + 2), then convert each term using the common denominator. Here's a start:
asked by Sara on July 19, 2007 
Algebra
(x)/(x3)4(2x5)/(x+2) I posted something before this, so now this is how far I got. The answer I know is (5x^217x9)/(x3)(x+2) first I get (x)(x+2)/(x3)(x+2) (4)(x3)(x+2)/(x3)(x+2)(2x5)(x3)/(x3)(x+2) Then I get
asked by Sara on July 20, 2007 
Algebra
(x)/(x3)4(2x5)/(x+2) I posted something before this, so now this is how far I got. The answer I know is (5x^217x9)/(x3)(x+2) first I get (x)(x+2)/(x3)(x+2) (4)(x3)(x+2)/(x3)(x+2)(2x5)(x3)/(x3)(x+2) Then I get
asked by Sara on July 20, 2007 
add maths
x^217x+52=0 The answer is 4,13 But i don't know how to do..
asked by mandy on January 26, 2014 
add maths
x^217x+52=0 The answer is 4,13 But i don't know how to do.. ASAP...
asked by mandy on January 26, 2014

Algebra
Solve: 5x3=11+12x; 17x3=11; 17x3+3=11+3= 17x=14; x= 14/17 is this right?
asked by A.W. on February 1, 2009 
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(3+7x)(16x2+15x2) (3+1x)(12x+16+0+18x2) Q4: (15+13x2+14x2)+(13x+18x) Q5: (2x2+1+15x2+7+3)+(0x+17x) Q6: (18x+3)+(17x2+1x2+9+8+0x) Q7: (6x + 14)  (9x + 5) Q8: (14x2 + 13x + 12)  (7x2 + 20x + 4) Q9: Subtract 10x2 + 16x  15 from
asked by Anonymous on January 10, 2007 
polynomials
(3+7x)(16x2+15x2) (3+1x)(12x+16+0+18x2) Q4: (15+13x2+14x2)+(13x+18x) Q5: (2x2+1+15x2+7+3)+(0x+17x) Q6: (18x+3)+(17x2+1x2+9+8+0x) Q7: (6x + 14)  (9x + 5) Q8: (14x2 + 13x + 12)  (7x2 + 20x + 4) Q9: Subtract 10x2 + 16x  15 from
asked by Anonymous on January 10, 2007 
BobPursley..here it is:
Problem 1: (x2)/(3x+4)  6x/(x+1) What I did: Common denominator is: (3x+4)(x+1) (x2)(x+1)/(3x+4)(x+1)  6x(3x+4)/(x+1)(3x+4) [(x2)(x+1)  6x(3x+4)] / (x+1)(3x+4) (x^2  x  2  18x^2  24x) / (x+1)(3x+4) x^2  18x^2 = 17x^2
asked by Margie on March 4, 2007 
to ms.sue
Lets say you had a book you bought at the book fair for $4.99. at a book order diouloge, there was a 10 book set for $27 with one of that book in it. what should you do with that book. I don't just want to give it away, I mean
asked by Celest on March 15, 2012