The number of students at another university increased from 14,000 students in 1971 to 30,000 in 1975. What was the percent increase in enrollment during this period?
30,000 - 14,000 = 16,000
16,000 / 14,000 = ?
Change the decimal answer to a percent.
Is it 1.14%?
Nope. You didn't convert the decimal to a percent.
16,000/14,000 = 1.1429 = 114.29%
Thank You!
You're welcome, Aleah/Jessie/Miguel/Nadia23/Shauna.
To calculate the percent increase in enrollment, you need to find the difference between the final enrollment number and the initial enrollment number, and then divide that difference by the initial enrollment number. The resulting value can then be multiplied by 100 to get the percentage increase.
Let's use the formula to find the percentage increase in this scenario:
Step 1: Calculate the difference:
Final enrollment number = 30,000
Initial enrollment number = 14,000
Difference = Final enrollment number - Initial enrollment number
Difference = 30,000 - 14,000
Step 2: Divide the difference by the initial enrollment number:
Percentage increase = (Difference / Initial enrollment number) * 100
Now, let's plug in the values and solve the equation:
Difference = 16,000
Percentage increase = (16,000 / 14,000) * 100
Upon calculating this, the percentage increase in enrollment during this period will be:
Percentage increase = (16,000 / 14,000) * 100
Percentage increase ≈ 114.29%
Therefore, there was approximately a 114.29% increase in enrollment during this period.