Mathematics

Prove that log a, log ar, log ar^2 is an a.p.

Is the following below correct?
Log ar^2 - Log ar= Log ar - Log a

hence applying laws of logarithm
Log(ar^2/ar) = log(ar/a)

Log and log cancels out and then cross-multiply
hence a^2r^2 = a^2r^2
L.H.S=R.H.S

Hence proved?

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  1. log a, log ar, log ar2, ...log a (r)^n

    now, log ar^n=log a + n log r
    consider the next term
    log ar^(n+1)= log a + (n+1)log r

    then

    log ar^(n+1)-log ar^n= log r which is a constant. Therefor, the progression is arithemetic.

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    bobpursley

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