a 46.2 mL, .568 M calcium nitrate soln is mixed w/ 80.5 mL of 1.396 M calcium nitrate soln. whats the concentration of final soln?

mols 1 + mols 2 = total mols
mols/volume in L = M

OH! thanks!
i got the right answer, 1.09 M.

To find the concentration of the final solution, you can use the equation:

mols1 + mols2 = total mols

First, calculate the number of moles in each solution:

For Solution 1:
Volume = 46.2 mL = 46.2 mL * (1 L / 1000 mL) = 0.0462 L
Molarity (M) = 0.568 M

moles1 = Molarity * Volume
moles1 = 0.568 M * 0.0462 L = 0.0262576 mol

For Solution 2:
Volume = 80.5 mL = 80.5 mL * (1 L / 1000 mL) = 0.0805 L
Molarity (M) = 1.396 M

moles2 = Molarity * Volume
moles2 = 1.396 M * 0.0805 L = 0.112278 mol

Now, add the moles from each solution to find the total moles:

total moles = moles1 + moles2
total moles = 0.0262576 mol + 0.112278 mol = 0.1385356 mol

Finally, divide the total moles by the total volume in liters to get the final concentration:

final concentration = total moles / total volume
final concentration = 0.1385356 mol / (0.0462 L + 0.0805 L) = 1.088 M

So, the concentration of the final solution is approximately 1.088 M.

Great job! You correctly calculated the concentration of the final solution as 1.09 M. To further explain the process, let's break it down step-by-step:

Step 1: Calculate the number of moles for each solution.
First, convert the volumes of both solutions to liters:
- For the first solution: 46.2 mL = 0.0462 L
- For the second solution: 80.5 mL = 0.0805 L

Next, use the formula: moles = concentration (M) × volume (L)
- For the first solution: moles of solution 1 = 0.568 M × 0.0462 L
- For the second solution: moles of solution 2 = 1.396 M × 0.0805 L

Step 2: Calculate the total moles of calcium nitrate.
Add the moles of solution 1 and solution 2 together:
total moles = moles of solution 1 + moles of solution 2

Step 3: Calculate the final concentration.
Divide the total moles of calcium nitrate by the total volume of the final solution (in liters).
final concentration (M) = total moles / (volume solution 1 + volume solution 2)

Plugging in the values:
final concentration (M) = total moles / (0.0462 L + 0.0805 L)

By performing the calculation, you correctly obtained the final concentration as 1.09 M. Well done!