Could someone please help me to slove this question.
(2y/x^2)+(7/x(x-3))
get a common denominator (x^2*x*(x-3)), combine the fractions.
Notice there is a y in the first numerator, and no y's in the denominator. Consequently, there will not be a lot of simplification on this.
To solve the given question, we need to combine the fractions and obtain a common denominator.
The given expression is: (2y/x^2) + (7/x(x-3))
Step 1: Find the common denominator
The common denominator can be found by multiplying the denominators of both fractions together. In this case, the two denominators are x^2 and x(x-3). Multiplying them will give us x^2 * x(x-3) = x^3(x-3).
Step 2: Rewrite the fractions with the common denominator
To do this, each fraction needs to be multiplied by a factor that will result in the common denominator. For the first fraction, we need to multiply by (x(x-3))/(x(x-3)). And for the second fraction, we need to multiply by (x^2)/(x^2).
After applying the multiplication, the expression becomes: (2y(x(x-3))/(x^2(x(x-3)))) + (7(x^2))/(x^2(x(x-3)))
Step 3: Combine the fractions
Now that we have the fractions with the same denominator, we can combine them. Since the denominators are the same, we can add the numerators together.
The resulting expression becomes: (2yx(x-3) + 7(x^2))/(x^3(x-3))
So, the simplified form of the given expression is (2yx(x-3) + 7(x^2))/(x^3(x-3)).