Tickets for a play at the community theater cost $4 for an adult and $2 for a child. If 250 tickets were sold and the total receipts were $740, how many of each type of ticket were sold?

Let x = number of tickets (adult)
Let (250 - x) = number of tickets (child)

Setting up the equation:

4x + 2(250 - x) = 740

Solve for x. Don't forget to include both types of tickets!

70

4x+2(250-x)=740

4x+500-2x=740
4x-2x=740-500
2x=240
x=120

To solve the equation, start by distributing the 2 to the terms inside the parentheses:

4x + 2 * 250 - 2x = 740

This simplifies to:

4x + 500 - 2x = 740

Combine like terms:

2x + 500 = 740

Next, subtract 500 from both sides of the equation:

2x = 740 - 500

This simplifies to:

2x = 240

Lastly, divide both sides of the equation by 2 to solve for x:

x = 240 / 2

x = 120

This means that 120 tickets were sold for adults. To find the number of child tickets sold, subtract x from the total number of tickets:

250 - 120 = 130

Therefore, 120 adult tickets and 130 child tickets were sold.

4x+2(250-x=740

4x+500-x=740
4x=740-500 cancellation, divide
4x=240 divide 240 by 4
x=60 ans. then substitute x value to neither equation and solve for y.