Tickets for a play at the community theater cost $4 for an adult and $2 for a child. If 250 tickets were sold and the total receipts were $740, how many of each type of ticket were sold?
Let x = number of tickets (adult)
Let (250 - x) = number of tickets (child)
Setting up the equation:
4x + 2(250 - x) = 740
Solve for x. Don't forget to include both types of tickets!
70
4x+2(250-x)=740
4x+500-2x=740
4x-2x=740-500
2x=240
x=120
To solve the equation, start by distributing the 2 to the terms inside the parentheses:
4x + 2 * 250 - 2x = 740
This simplifies to:
4x + 500 - 2x = 740
Combine like terms:
2x + 500 = 740
Next, subtract 500 from both sides of the equation:
2x = 740 - 500
This simplifies to:
2x = 240
Lastly, divide both sides of the equation by 2 to solve for x:
x = 240 / 2
x = 120
This means that 120 tickets were sold for adults. To find the number of child tickets sold, subtract x from the total number of tickets:
250 - 120 = 130
Therefore, 120 adult tickets and 130 child tickets were sold.
4x+2(250-x=740
4x+500-x=740
4x=740-500 cancellation, divide
4x=240 divide 240 by 4
x=60 ans. then substitute x value to neither equation and solve for y.