how many grams of sulfur are needed to react w/ 246 grams of mercury to form HgS?
Hg + S ==> HgS unless your instructor insists on writing S as S8, in which case it will be
8Hg + S8 ==> 8HgS.
The answer will be the same no matter which way the equation is written. I shall be happy to check your work. This is freshman chemistry stoichiometry.
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To determine the number of grams of sulfur needed to react with 246 grams of mercury, we first need to balance the chemical equation for the reaction:
Hg + S --> HgS
The molar mass of mercury (Hg) is 200.59 g/mol, and the molar mass of sulfur (S) is 32.07 g/mol.
Next, we need to convert the given mass of mercury (246 grams) to moles. We can do this by using the molar mass of mercury:
246 g Hg * (1 mol Hg / 200.59 g Hg) = 1.227 mol Hg
According to the balanced chemical equation, the ratio of mercury to sulfur is 1:1. This means that for every 1 mole of mercury, we need 1 mole of sulfur.
Therefore, the number of moles of sulfur required is also 1.227 mol.
Finally, we can convert the moles of sulfur to grams by using the molar mass of sulfur:
1.227 mol S * (32.07 g S / 1 mol S) = 39.38 g S
Therefore, 39.38 grams of sulfur are needed to react with 246 grams of mercury to form HgS.