okay guys, just one more word problem. and i don't think this one has any typos in it:
The perimeter of a rectangle is 27 cm and its area is 35 square centimeters. Find the length and the wide of the rectangle.
i just need help getting it started...
Ok P=27cm where P is the perimeter. A = 35cm^2 where A is the area.
We know that A =L*W and P=2(L+W) thus we have
(1) 35=L*W
(2) 27=2(L+W)
From (1) we have 35/L = W. Use this in (2) to get
27=2(L + 35/L) Now solve for L. This is a quadratic equation.
thanks a lot. i had been trying to do this for a long time :)
Velocity of 10 meters per second from the top of a 24 meter high cliff and it misses the cliff on the way down when will the rock be 4 meters from the water below?
y=x2-10x
# people have a combined height of 10 ft. 9 inches. A is 9 inches shorter than B, who is 6 inches taller than C. How talle are A,B, and C?
3 people have a combined height of 10 ft. 9 inches. A is 9 inches shorter than B, who is 6 inches taller than C. How talle are A,B, and C?
y=x(x-10)
x=0
x-10=0
solutions=0 and 10
rjty
The hypotenuse or a right angle has a length of 13 cm. The sum of the lengths of the other two sides is 17. Find the unknown side lengths.
Let's solve this problem using the Pythagorean theorem. According to the theorem, in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b).
In this case, we know that the hypotenuse (c) has a length of 13 cm, and the sum of the lengths of the other two sides (a and b) is 17 cm.
So, we can write the equation as:
a^2 + b^2 = c^2
Substituting the known values into the equation, we have:
a^2 + b^2 = 13^2
a^2 + b^2 = 169
Now, we need to find the possible values for a and b that satisfy this equation.
We can start by trying different pairs of numbers whose squares add up to 169. Let's begin with a = 1 cm. If a = 1 cm, then b = 169 - a^2 = 169 - 1 = 168 cm. However, if we plug these values back into the equation, we see that it doesn't satisfy the equation.
Next, let's try a = 2 cm. If a = 2 cm, then b = 169 - a^2 = 169 - 4 = 165 cm. Again, plugging these values back into the equation, we find that it doesn't satisfy the equation.
We can continue this process and try different values for a and find the corresponding values of b until we find a pair that satisfies the equation. However, it seems that there is no integer solution to this problem. Hence, there are no integers that satisfy the given conditions for the unknown side lengths.