Liquid methanol (CH3OH) is combusted in oxygen gas to yield carbon dioxide gas and liquid water

Okay I keep getting this:
CH3OH(l) + 1.5 O2(g) > CO2(g) + 2 H2O(l)
the website tells me I'm wrong, but I don't know how to go about with out using fractions. Please help. Thanks

CH3OH(l) + 1.5 O2(g) > CO2(g) + 2 H2O(l)

You get rid of fractions in chemistry the same as in math. If it's a 1/2, just multiply by 2.
2CH3OH + 3O2 ==> 2CO2 + 4H2O
For 1/3 multiply by 3.For 1/4 multiply by 4, etc.
MOST times we need whole numbers to balance an equation. The only time that fractions are ok is in thermodynamic equations.

thank you sooo much

When balancing the equation for the combustion of liquid methanol (CH3OH), it is important to ensure that the number of atoms of each element is equal on both sides of the equation. To balance the equation without using fractions, you can follow these steps:

Step 1: Start by counting the number of atoms of each element on each side of the equation.
On the left side, we have:
1 Carbon (C)
4 Hydrogen (H)
1 Oxygen (O)

On the right side, we have:
1 Carbon (C)
4 Hydrogen (H)
3 Oxygen (O)

Step 2: Begin by balancing the carbon atoms.
Since there is only 1 carbon atom on each side of the equation, the carbon atoms are already balanced.

Step 3: Move on to balance the hydrogen atoms.
On the left side, we have 4 hydrogen atoms while, on the right side, we only have 2 hydrogen atoms. To balance the hydrogen atoms, we place a coefficient of 2 in front of H2O.
The equation now becomes:
CH3OH(l) + 1.5 O2(g) -> CO2(g) + 2 H2O(l)

Step 4: Finally, balance the oxygen atoms.
On the left side, we have 1 oxygen atom in CH3OH and 1.5 oxygen atoms in 1.5 O2 (since 1 molecule of O2 consists of 2 oxygen atoms). This gives us a total of 1 + 1.5 = 2.5 oxygen atoms on the left side.
On the right side, we have 2 oxygen atoms in CO2 and 4 oxygen atoms in 2 H2O, giving us a total of 2 + 4 = 6 oxygen atoms on the right side.

To balance the oxygen atoms, we can multiply the entire equation by 2 to obtain whole number coefficients. This gives us:
2 CH3OH(l) + 3 O2(g) -> 2 CO2(g) + 4 H2O(l)

Now the equation is balanced, with equal numbers of atoms of each element on both sides.