Solve by using the quadratic formula
x^2=-7x+12
First, put all the terms on one side.
x^2=-7x+12
x^2 + 7x -12 = 0
If the original sign for the 12 were negative, this would lead you to:
x^2 + 7x + 12 = 0
This could factor into:
(x+3)(x+4) = 0
However, as you have formula posted, it cannot be factored.
I hope this helps. Thanks for asking.
x=(-7/2)+(sq97)/(2),(-7/2)-(sq97)/(2)
To solve the equation x^2 = -7x + 12 using the quadratic formula, you need to identify the coefficients a, b, and c in the general quadratic equation form ax^2 + bx + c = 0.
In this case, a = 1, b = -7, and c = 12.
Now, substitute these values into the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
x = (-(-7) ± √((-7)^2 - 4(1)(12))) / (2(1))
x = (7 ± √(49 - 48)) / 2
x = (7 ± √1) / 2
x = (7 ± 1) / 2
Now, we have two possible solutions:
x1 = (7 + 1) / 2 = 8 / 2 = 4
x2 = (7 - 1) / 2 = 6 / 2 = 3
Therefore, the solutions to the equation x^2 = -7x + 12 are x = 4 and x = 3.
I hope this explanation helps you understand how to solve quadratic equations using the quadratic formula. Let me know if you have any more questions!