a chemist mixes an 11% alchohol solution with an 8% alchohol solutoins. How many milliliters of each solution should he use to make a 600ml solution that is 8% alchohol solution?
Why wouldn't we just use 600ml of the 8% solution to begin with? So 0ml of the 11% and 600ml of the 8% and we're done. Does that work? What am I missing?
*scratch scratch* yes, very algebraically solved :)
Be sure there isn't a typo and the second is supposed to be a 6% solution. Then we could mix the 11% and 6%(or some solution less than 8%) to make an 8% solution.
I am sure there is a typo somewhere.
no that is exactly what the problem says
Then the problem obviously has a typo in it.
How do you do square roots or ten powers?
sincerly confuesed
How do you do square roots and ten powers?
sincerly
confused
Shay could you start a new question and state what the problem is asking, please.
To solve the problem, we need to set up an equation based on the given information. Let's assume that the chemist will use x milliliters of the 11% alcohol solution and (600 - x) milliliters of the 8% alcohol solution.
The equation for the amount of alcohol in the mixed solution can be written as:
0.11x + 0.08(600 - x) = 0.08(600)
Let's simplify this equation:
0.11x + 48 - 0.08x = 48
Combine like terms:
0.03x = 0
Divide by 0.03:
x = 0
According to the equation, the chemist will need to use 0 milliliters of the 11% alcohol solution and 600 milliliters of the 8% alcohol solution to make a 600ml solution that is 8% alcohol.
However, this answer doesn't make sense because it implies that no alcohol is present in the final solution. It's possible that there is a typo in the problem or some missing information. It would be best to double-check the problem statement or consult your teacher to ensure accuracy.