I was wondering if you could help me with this problem.
If the reaction proceeds with a 96.8% yield, how many kilograms of CaSO4 are formed when 5.34 kg SO2 reacts with an exfess of CaCO3 and O2?
Thanks for your help.
Write the equation for the reaction and balance it.
CaCO3 + SO2 ==> CaSO4 + ??
Change 5.34 kg SO2 to grams.
Change grams SO2 to mols. # mols = grams/molar mass SO2.
There is 1 mol SO2 in a mol of CaSO4; therefore, there will be the same number of mols formed of CaSO4 that you have of SO2 initially (at 100% yield).
Change mols CaSO4 to grams using mols = g/molar mass.
Change grams CaSO4 to kg.
kg CaSO4 @ 96.8% yield = kg CaSO4 @ 100% yield x 0.968.
Post your work if you get stuck.
136kg
Sure, I'd be happy to help you with this problem!
The chemical equation for the reaction is:
CaCO3 + SO2 -> CaSO4 + ?? (balanced equation)
To solve the problem, we need to follow these steps:
1. Convert the given mass of SO2 from kilograms to grams:
Since 1 kg = 1000 grams, multiply 5.34 kg by 1000 to get 5340 grams of SO2.
2. Convert grams of SO2 to moles:
Use the molar mass of SO2 (sulfur dioxide) to convert grams to moles. The molar mass of SO2 is approximately 64.06 grams/mol.
Divide the mass of SO2 (5340 grams) by the molar mass (64.06 grams/mol) to get the number of moles of SO2.
3. Determine the number of moles of CaSO4 formed:
Since the balanced equation shows a 1:1 ratio between SO2 and CaSO4, the number of moles of CaSO4 formed will be the same as the moles of SO2.
Therefore, the number of moles of CaSO4 formed is equal to the number of moles of SO2.
4. Convert moles of CaSO4 to grams:
Use the molar mass of CaSO4 (calcium sulfate) to convert moles to grams. The molar mass of CaSO4 is approximately 136.14 grams/mol.
Multiply the number of moles of CaSO4 by the molar mass (136.14 grams/mol) to get the mass of CaSO4 formed in grams.
5. Convert grams of CaSO4 to kilograms:
Divide the mass of CaSO4 in grams by 1000 to convert it to kilograms.
6. Account for the yield:
Multiply the mass of CaSO4 obtained at 100% yield (in kilograms) by the yield percentage (96.8% = 0.968) to find the mass of CaSO4 formed at the stated yield.
I hope this helps! If you have any further questions or get stuck along the way, please feel free to ask.