If circle A has equation (x+2)^2+(y+2)^2=4, which point is in its exterior?
The radius is 2, so any x or y greater than two from the center (-2,-2) will be outside
To determine which points are in the exterior of circle A with the equation (x+2)^2+(y+2)^2=4, you can compare the coordinates of the points to the center and radius of the circle.
The given equation represents a circle with its center at (-2,-2) and a radius of 2. The center of the circle is obtained by negating the values inside the parentheses.
To determine which points are in the exterior of the circle, you need to identify the points that are located outside the circle. Any point with coordinates (x,y) that is farther away from the center (-2,-2) than the radius of the circle (2 units) is considered to be in the exterior.
In this case, the x-coordinate and y-coordinate of the center are both -2. So, any point with an x-coordinate greater than -2 or a y-coordinate greater than -2 will lie in the exterior of the circle.
Therefore, any point that satisfies either of the following conditions will be in the exterior of circle A:
1. x > -2
2. y > -2
You can take any point whose coordinates fulfill one or both of these conditions to be in the exterior of the circle.