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algebra
Can someone please help me with this one? Solve (5x+4)^1/23x=0 Just so you know, it is to the 1/2 power. Add 3x to both sides of the equation, then square both sides. That should enable you to gather terms and factor. Yeah,
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radical equation
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asked by jessica on June 29, 2006 
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how can i simplify this more its for the following problem: Problem #22 solve by using the quadratic formual. 5x^24x+1=0 this is where i am but i do not know how to go further. x = (4 (+/) sqrt (4))/(10) Problem #23 Solve by
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Find the polynomials roots to each of the following problems: #1) x^2+3x+1 #2) x^2+4x+3=0 #3) 2x^2+4x5 #3 is not an equation. Dod you omit "= 0" at the end? #2 can be factored into (x+1)(x+3) = 0, so the roots are x=1 and 3.
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math,help,algebra I
I need help can someone help me get unstuck and let me know if i am correct.thank you. solve by completing the square. 4x^2+2x3=0 this is what i am doing: i used the quadratic equation. so where i am is in this step: x = (2 (+)
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math
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physics repost
I am still trying to solve for H in this equation but I am still lost MgH = (1/2)*k*(H210)^2 + Mg*2 I was told to expand the square on the right, gather terms, put it in the standard quadratic form, and use the quadratic
asked by Chris Adison on April 24, 2008 
physics repost
I am still trying to solve for H in this equation but I am still lost MgH = (1/2)*k*(H210)^2 + Mg*2 I was told to expand the square on the right, gather terms, put it in the standard quadratic form, and use the quadratic
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math,algebra
can someone help me out factor out this 0=16t^2122t+180 i have so far this but the last one i am not sure 8(2t^214t + ?) you need to use the quadratic formula: b(+or)[sqrt(b^24ac)/2a] so you are saying that i don't have to
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Algebra
Solve for s: h=(square root of 3)times s/2 and solve for h V= (pi)r squared h / 3 Solve for s: h=(square root of 3)times s/2 Multiply both sides by 2. 2h = (sqrt 3)*s*2/2 which cancels the 2 on the right. 2h = (sqrt 3)*s Now
asked by Jamie on August 17, 2006