A racecar driver in an 825-kg car accelerates from rest to a velocity of 21.5 m/s in 0.55 s. What is the net force acting on the car?
I found out using A=v/t that the horizontal acceleration is 39.1 m/s^2. My problem now is this...
Is the net force just F=ma? Or do I have to take account for gravity and somehow find the vector sum???
Force=ma= m * 21.5/.55 Newtons
Yes, in the horizontal, this is it, gravity is in the vertical. We ignored friction in this, in the real world friction (caused partially by gravity) would have to be added.
Ok, so finding Fnet is as simple as F=ma? Thanks!
wwhat is the kinetic energy of a 1500kg car with a velocity of 72km/r B.... how much work must be done on ths car to bring it to a complete stop
To find the net force acting on the car, you can use Newton's second law, which states that the net force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).
In this case, the mass of the car is given as 825 kg, and you have already calculated the acceleration to be 39.1 m/s^2. So, you can simply multiply the mass and the acceleration to find the net force:
F = m * a = 825 kg * 39.1 m/s^2 = 32,257.5 N
Therefore, the net force acting on the car is 32,257.5 Newtons.
Regarding your question about gravity, it depends on the context. In this specific scenario, where the car is accelerating horizontally, you do not need to consider the force of gravity. The net force is determined by the acceleration produced by the engine and other external factors, while the force of gravity is acting vertically downward but does not affect the horizontal acceleration of the car.