Trapezoid. Height is 16m, one base is
2
20m, and the area is 224 m what is the length of the other base?
The dimensions of area are m^2, not m.
I assume that your entry of "2" was a mistake, and that you meant 20m for one of the base lengths.
Trapezoid Area = (average base width) x height
= (1/2) (b1 + b2) h
b1 (the base width that you know)= 20
Area = 8(20 + b2)
= 224
20 + b2 = 224/8 = 28
b2 = ?
If a circle has 81 square centimeters and a circumference of 16 centimeters then what is the radius?
To find the length of the other base (b2), we can use the formula for the area of a trapezoid.
First, let's rearrange the formula to solve for b2:
Area = (1/2) * (b1 + b2) * h
Given that the height (h) is 16m and one base (b1) is 20m, and the area is 224m^2, we can substitute these values into the formula:
224 = (1/2) * (20 + b2) * 16
Now, let's solve for b2:
Multiply both sides of the equation by 2 to remove the fraction:
224 * 2 = (20 + b2) * 16
448 = 20 + b2 * 16
Subtract 20 from both sides of the equation:
448 - 20 = b2 * 16
428 = b2 * 16
Divide both sides of the equation by 16 to isolate b2:
428 / 16 = b2
b2 ≈ 26.75
Therefore, the length of the other base (b2) is approximately 26.75m.