I need help setting up this problem or atleast if I am on the write track to solving it.
The Jurassic Zoo charges $28.00 for each adult admission and $12.00 for each child. The total bill for 454 people from a school trip was $3860.00. How many adults and how many children went to the zoo?
this is what I have so far
a+c=454
28(454-c)+12c=3860
your equation is correct according to your information, but the solution for c obviously has to be a positive whole number
I get c = 553.25
besides having a "partial child" there would then have be a negative number of adults.
(with the 454 being all children would already cost $5448)
Check your typing or read the question again.
You're on the right track in setting up the problem. To solve this type of problem, you can create a system of equations based on the given information.
Let's define the variables:
Let 'a' represent the number of adult admissions
Let 'c' represent the number of child admissions
Based on the given information, we know that the total number of people that went to the zoo is 454. Therefore, we can set up the equation:
a + c = 454
Next, we know that the total bill for the admissions was $3860. With adults being charged $28.00 and children being charged $12.00, we can set up the equation for the total cost:
28a + 12c = 3860
Now, you have a system of two equations. The goal is to solve for the values of 'a' and 'c'. There are several methods to solve a system of equations, such as substitution, elimination, or graphing.
One common method is substitution. From the first equation, we can isolate 'a' as follows:
a = 454 - c
We can substitute this expression for 'a' into the second equation:
28(454 - c) + 12c = 3860
Now, you can simplify and solve for 'c'. Once you find the value of 'c', you can substitute it back into the first equation to find the value of 'a'.